An object is placed 20 cm in front of a concave mirror with a focal length of 10 cm. Find the image distance.
\[ \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \Rightarrow \frac{1}{10} = \frac{1}{20} + \frac{1}{v} \]
\[ \frac{1}{v} = \frac{1}{10} - \frac{1}{20} = \frac{1}{20} \Rightarrow v = 20\ \text{cm} \]
The image is real, inverted, and the same size as the object.
An object is placed 10 cm from a concave lens of focal length -20 cm. Find the image distance.
\[ \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{-20} = \frac{1}{v} - \frac{1}{-10} \]
\[ \frac{1}{v} = -\frac{1}{20} + \frac{1}{10} = \frac{1}{20} \Rightarrow v = 20\ \text{cm} \]
The image is virtual, upright, and diminished, located 20 cm on the same side of the lens.