Enthalpy Level Diagrams

Exothermic Reactions

Endothermic reactions

Hess's Law

Hess’s law of heat summation states that for a chemical equation that can be written as the sum of two or more steps, the enthalpy change for the overall equation equals the sum of the enthalpy changes for the individual steps.


In other words, no matter how you go from given reactants to products (whether in one step or several), the enthalpy change for the overall chemical change is the same.


Consider the following reaction:

\(\ce{A + B -> C + D}\)\(\; \; \; \; \; \; \Delta \text{H}_\text{x}\)

The enthalpy change for the reaction that forms products C + D directly (\(\Delta \text{H}_\text{x}\)) will be the same as the sum of the enthalpy changes for the production of C + D via an indirect route where intermediate products are formed and subsequently react to produce C + D.


This is shown in the diagram below.

One method of calculating an enthalpy change for a process involves rearranging a set of given reaction equations with known values.


The following points must be noted when manipulating equations:

Calculate the enthalpy for this reaction:

2C(s) + H2(g) ---> C2H2(g)

ΔH° = ??? kJ

Given the following thermochemical equations:

Solution:

  1. Determine what we must do to the three given equations to get our target equation:
    • first eq: flip it so as to put C2H2 on the product side
    • second eq: multiply it by two to get 2C
    • third eq: do nothing. We need one H2 on the reactant side and that's what we have.
  2. Rewrite all three equations with changes applied:

Final reaction:

2C(s) + H2(g) ---> C2H2(g)

ΔH° = 226.7 kJ


Written by Fillios Memtsoudis